Given an integer, say 287591, we want to calculate the sum of all its digits. The result would be 32 = 2+8+7+5+9+1. This problem was already considered in the while-loop section (example 6). Now we are solving it with a for-loop.
How do we proceed with a for-loop? We change the integer into a string! Python allows us to iterate over the characters in the string and while doing so we add up “the digits.” Note that in the for-loop we need to convert the character “5” into digit 5 before making the addition.
1 2 3 4 5 6 7 8 9 10 11 | # 02Loops example_11 SumDigits2.py# add up the digits in an integer using a for loopn = int(raw_input("Please input an integer:")) sum = 0for i in str(n): #Convert integer sum into a string #Convert the string reresenting a single digit into an integer and add sum = sum + int(i) print(sum) |
The following video uses this problem in a nested loop setting. Video Length: 4:33
